Home >Documents >Desain Jembatan Staadpro,Jimmy, 3 Mrk1,1341320066

Desain Jembatan Staadpro,Jimmy, 3 Mrk1,1341320066

Date post:15-Apr-2016
Category:
View:37 times
Download:5 times
Share this document with a friend
Description:
Desain Jembatan Staadpro,Jimmy, 3 Mrk1,1341320066
Transcript:
  • Mu = 8.00E+07 Nmmfy = 240 Mpafc' = 30 Mpab = 200 mmh = 600 mmd' = 30 mmd = 570 mm

    m =

    m = 9.4117647059

    h =Rn = 1.5389350569

    = 0.0066183597

    As = 754.49300424 16

    As baru = 804.24771932

    a = 35.505553139

    Mn = 106594456.79= 85275565.429 > 8.00E+07

    OkeMn

  • Cc = 0,85.fc'.a.b

    a

    600

    Ts = As.fy

    b = 200

  • P = 10 TL = 1.8 mMu = 4.5 T.m

    = 45000000 Nmm1.6 Mu = 72000000 Nmmfy = 240 Mpafc' = 25 Mpa

    Potongan Plat Tampak Depan

    m = 11.294117647 mmb = 1000 mmh = 200 mm 200 mmd' = 30 mmd = 170 mm

    Pakai TulanganL =

    Rn = 3.1141868512As Bagi =As Terpasang =

    = 0.0140981806As = 2396.6907012As coba = 2820

    a = 31.849411765

    Mn = 104278159.06 Nmm= 83422527.247 Nmm > 72000000 Nmm

    Tulangan Oke

    Pakai Tulangan - 100

    mm2mm2

    Mn

    vv vv

  • Potongan Plat Tampak Depan19 - 100 10 -

    10 - 27 Pakai Tulangan 101800 mm B = 1000

    400400

    mm2mm2

    vv vv vv vvvv vv

  • 175

    - 27mm

  • Mu = 180 kNm= 180,000,000.00 Nmm

    fy = 400 Mpafc' = 25 Mpab = 200 mmh = 600 mmd' = 40 mmd = 560 mmAs1 = 500

    a = 47.0588235294 mm

    Mn1 = 107,294,117.65 Nmm

    = 90,882,352.94 As' = 436.9344

    = 436.9343891403

    = 936.9343891403jadi pakai

    4 D 19 h = 600

    = 436.9343891403jadi pakai

    2 D 19b = 200

    As total = 936.9344

    mm2=(.)/(0.85 . ^. )

    1 .=. (/2)

    _ = 2 ( ( 1) )/

    2=^= _(2 )/( . (^))

    1 2= +

    ^ 2=

  • Cc = 0.85 . fc' . A . BCs = As' . fy

    Mn1d-a/2 d-d'

    Ts1 = As1 . fy Ts2 = As2. .fymm As1 = 500 As2 = 436.9343891403

    Mn1mm2 134,117,647.059

    Mn total 247,720,588.24 > 180,000,000.00 Tulangan Oke

    mm2

  • Mn2

    Mn2 113,602,941.18

  • L = 6 mMu = 300,000,000.00 Nmmfy = 400 Mpafc' = 15 Mpabw = 200 mmh = 600 mmhf = 200 mmd' = 30 mmd = 570 mmAs = 1700

    1/4 L = 1500 mmbw + 16 . hf = 3400 mm bef = 1500 mm

    Jb = 1800 mma = 35.56 mm

    Cc>Ts, a 300,000,000.00 Nmm

    Jadi digunakan penulangan4 D 25

    mm2

  • bef = 1500 mm Cc awal =

    hf = 200

    Cc Baru =

    Cc>Ts, a

  • 3,825,000 N

    680,000 N

    680,000 N

  • Mu = 5,000,000.00 Nmmfy = 400 Mpafc' = 15 Mpabw = 200 mm hf = 120h = 600 mmhf = 120 mmd' = 40 mmd = 560 mmAs = 50001/4 . L = 1500 mmbw + 16.hf = 2120 mm bef = 750 mmJb = 750 mm

    = hf + (As . fy - 0.85 . fc' . bef . Hf) / (0.85 . fc' . bw)= 454.314 > 120 mmTs>Cc, maka a>hf, sehingga blok tekan masuk balok dibawah plelat, jadi termasuk balok T-murni

    Mn = 0.8 . (Cc1 . (d - hf )) + Cc2 . (d - hf - (a - hf)/2))Mn = 645,079,019.61 Nmm > 5,000,000.00 Nmm

    OkJadi digunakan tulangan

    7 D 32

    mm2

    a T-murnia T-murni

  • bef = 750==

    ==

    Ts ==

    bw = 200Ts =

    Ts>Cc, maka a>hf, sehingga blok tekan masuk balok dibawah plelat, jadi termasuk balok T-murni =

    Cc1

    Cc2

  • 0.85 . fc' . hf . bef 1,147,500.00 N

    0.85 . fc' . (a-hf) bw852500.0 N

    As.fy 2,000,000.00 N

    Cc1 + Cc2 2,000,000.00 N

  • Mu = 70 tm 700000000 NmmPu = 50 t 500000 Nmme = 1400 mmfy = 400 Mpafc' = 30 Mpa abb = 800 mmh = 800 mmd' = 40 mmd = 760 mmAs = 3000 mm2As' = 1500 mm2m = 15.686275 = 0.0049342

    = 0.85Cb = 456 mmab = 387.6 mm

    = 0.0027368fs' = 547.36842 fs'=fy 400 Mpa

    5 D 29Cc = 7907040 NCs = 600000 N Pnb = 7307040 NTs = 1200000 N

    4749576 > 500000Hancur tarik

    Pn = 846439.7 NPn = 550185.81 N > 500000 N

    OKJadi, penulangan pakai

    5 D 29

    1

    s'

    Pnb

    =0.85 . ^. . . [( 2)/ + 2 ((( 2)/2)^2+ .2 . (1 /) )]

  • Pnb

    Cs = As.fs'

    CbCc = 0.85.fc'.ab.b

    Ts = As . fy

    5 D 29

    cu = 0.003s'

    s

  • Mu = 10 tm 100000000 NmmPu = 120 t 1200000 Nmme = 83.33 mmfy = 400 Mpa Pnbfc' = 25 Mpab = 400 mmh = 400 mmd' = 40 mm abd = 360 mmAs = 2000 mm2As' = 1500 mm2 Ts = As . Fy

    = 0.85Cb = 216 mmab = 183.6 mm

    = 0.0024444444fs' = 488.88888889 fs'=fy 400 Mpa

    Cc = 1560600 NCs = 600000N Pnb = 1360600 NTs = 800000 N

    884390 N < 1200000Hancur tekan

    Pn = 2838679.4609 N= 1845141.6496 N > 1200000 N

    OKJadi penulangan pakai

    4 D 29

    1

    s'

    Pnb

    Pn

    = (^. )/(/( )+0.5)+ ( . . )/((3 . . )/^2+1.18)

  • Cs = As' . Fs' cu = 0.003

    CbCc = 0.85 . Fc' . Ab . B

    Ts = As . Fy

    4 D 29

    N12 D 29

    s'

    s

  • Data - datafc' = 25 Mpafy = 400 MpaMu = 45000 kgm

    = 450 kNm= 450000000

    Pu = 87.3 t= 873000 N

    e = 515.4639175258 mmfy = 400 Mpafc' = 25 Mpab = 450 mmh = 600 mmd' = 60 mmd = 540 mmAs = 2000 mm2As' = 1000 mm2As total = 3000 mm2

    m = 18.8235294118

    = 0.0082304527 = 0.02709375= 0.85

    Cb = 324 mmab = 275.4 mm

    = 0.0024444444fs' = 488.8888888889 Mpa fs=fy = 400

    Cc = 2633512.5Cs = 400000Ts = 800000

    = 715419078.75

    = 0eb = 320.311204325

    e>eb, maka hancur tarik pakai

    1

    s'

    M

    =0.75._ _._ =1.4 _ /_ ..

    = / _(0.85 )._

    = / _)(.

    =0.85 _1 (600/. _ /_(600 ))+_

    = _(600 )/.(600 )+_

    ^= _(0.003 )) (_ /_

    =0.85 ^_ ._ .._ = ^_ _ ._

    = ._ _ _

    .(/2 /2) (/2 ) _=_ +_ +_(/2 )

  • No. Mu (kNm) Pu (kN) e1 450 800 562.52 320 1200 266.673 200 7000 28.574 120 4000 305 450 5000 906 200 1200 166.667

    Koordinat (Mn, Pn) diagram interaksic a Cc Mn sample Pn sample

    mm mm N kNm kN49.3 41.91 400716.6 399.818955 0.716562560 51.00 487687.5 421.870219 87.687585 72.25 690890.6 470.308764 290.890625

    110 93.50 894093.8 514.429242 494.09375135 114.75 1097297 554.231654 697.296875160 136.00 1300500 589.716 900.5185 157.25 1503703 620.882279 1103.70313210 178.50 1706906 647.730492 1306.90625235 199.75 1910109 670.260639 1510.10938260 221.00 2113313 688.472719 1713.3125310 263.50 2519719 711.94268 2119.71875335 284.75 2722922 717.200561 2322.92188324 275.40 2633513 715.419079 2233.5125360 306.00 2926125 718.140375 2526.125390 331.50 3169969 713.568305 2769.96875420 357.00 3413813 702.778219 3013.8125450 382.50 3657656 685.770117 3257.65625480 408.00 3901500 662.544 3501.5510 433.50 4145344 633.099867 3745.34375600 510.00 4876875 507.459375 4476.875700 595.00 5689688 302.224219 5289.6875

    0 6138_ =0)=0.85 ^( ._ . ^ . +_ ._

    0 100 200 300 400 500 600 700 8000

    1000

    2000

    3000

    4000

    5000

    6000

    7000

    8000 Diagram Interaksi M-P

    Mn sample

    Pn Sample

    Lentur

    Tekan Murni

    e=eb

  • 0 100 200 300 400 500 600 700 8000

    1000

    2000

    3000

    4000

    5000

    6000

    7000

    8000 Diagram Interaksi M-P

    Mn sample

    Pn Sample

    Lentur

    Tekan Murni

    e=eb

  • Pnb

    Cs = As' . Fs'

    cbCc = 0.85 . Fc' ab . b

    Ts = As . Fy

    Mpa

    NN Pnb = 2233513 NN

    8 D 22

    cu =0.003s'

    s

    _=_+__

  • 0 100 200 300 400 500 600 700 8000

    1000

    2000

    3000

    4000

    5000

    6000

    7000

    8000 Diagram Interaksi M-P

    Mn sample

    Pn Sample

    Lentur

    Tekan Murni

    e=eb

  • 0 100 200 300 400 500 600 700 8000

    1000

    2000

    3000

    4000

    5000

    6000

    7000

    8000 Diagram Interaksi M-P

    Mn sample

    Pn Sample

    Lentur

    Tekan Murni

    e=eb

  • Vu = 180 kN = 180000 Na = 125 mmbw = 250 mmh = 460 mmd' = 110 mmd = 350 mmfc' = 35 Mpafy = 400 MpaMenentukan luas tulangan geser friksi

    = 300000 N

    = 612500 N > 300000

    = 481250 N > 300000

    hub. Konsol - 1Avf = 750 mm2

    Menentukan luas tulangan tarikNuc = 0.2 . Vu

    = 36000 N

    Mu = 26460000 Nmm

    Af = 370.58824 mm2

    Menentukan luas tulangan tarik

    = 150 mm2Luas tulangan akhir, As

    = 520.5882= 650 mm2

    = 306.25 mm2As terbersar = 650 mm2 3 D 19

    kolom tidak monolit, maka

    _=/

    0.2 . ^. _ .

    5.5 . .

    = _/( . )

    . . ( )= +

    = /( . . 0.85 . )

    = ( . . . ( ) + )/( . . 0.85 . )

    = /(.)

    = 2/3 +=+

    =0.04 /

  • Luas tulangan horizontal pembagi, Ah

    = 250 mm2 4 D 10Luas landasan, Al

    = 13186.813 mm2 jadi luas perlu adalahsisi = 114.83385 mm = 115 mm x 115

    =1/2 )(

    Vu < . 0.6 . fc' . Al =/(.0.6 . )

  • mm

  • Mu = 12.3 tm = 123000000 NmmPu = 100 t = 1000000 Ne = 123 mmfy = 400 Mpafc' = 25 Mpab = 1000 mmh = 400 mmd' = 40 mmd = 360 mmAs = 2530 mm2As' = 1265 mm2m = 18.82353 = 0.007028

    = 0.85Cb = 216ab = 183.6

    = 0.002444fs' = 488.8889 fs' = fy = 400 MpaCc = 3901500 NCs = 506000 N Pnb = 3395500 NTs = 1012000 N

    2207075 N > 1000000 NHancur Tarik

    Pn = 5690940 N= 3699111 N > 1000000 N

    OKJadi penulangan tarik pakai

    22 - 150

    Jadi penulangan tekan pakai22 - 300

    Mu = 29.187 tm = 291870000 NmmPu = 192 t = 1920000 Ne = 152.0156 mmfy = 400 Mpafc' = 25 Mpab = 10000 mm

    1

    s'

    Pnb

    Pn

    =0.85 . ^. . . [( 2)/ + 2 ((( 2)/2)^2+2 . . . (1 /) )]

    D

    D

    h

  • h = 1000 mmd' = 100 mmd = 900 mmAs = 3000 mm2As' = 1500 mm2m = 18.82353 = 0.000333

    = 0.85Cb = 540ab = 459

    = 0.002444fs' = 488.8889 fs' = fy = 400 MpaCc = 97537500 NCs = 600000 N Pnb = 96937500 NTs = 1200000 N

    63009375 N > 1920000 NHancur Tarik

    Pn = 1.5E+008 N= 97891611 N > 1920000 N

    OKJadi pe

Click here to load reader

Embed Size (px)
Recommended